Q. $sp^{3}$ hybridisation is found in

A) ${CO}_{3}^{2 -}$
B) $BF_{3}$
C) ${NO}_{3}^{-}$
D) $NH_{3}$
Explanation

(d)
In $NH_{3}$, N undergoes $sp^{3}$ hybridisation. Due to the presence of one lone-pair, it is pyramidal in shape.
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Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.