Q. The state of hybridisation of S in $SF_{4}$ is
A) $sp^{3}$ and has a lone pair of electron
B) $sp^{2}$ and has tetrahedral structure
C) $sp^{3}d$ and has a trigonal bipyramidal structure
D) $sp^{3}d^{2}$ and has an octahedral structure
Explanation
(c)
S in $SF_{4}$ possesses trigonal bipyramidal structure with $sp^{3}d$ hybridisation.
S in ground state
[image:4_image159.emf]
S in excited state
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.