Q. The electronic structure of four elements $A,B,C,\ D$ are $(A)1s^{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (B$)$1s^{2},2s^{2},2p^{2} (C)1s^{2},2s^{2},2p^{5}$ $(D)1s^{2},2s^{2},2p^{6}$ The tendency to form electrovalent bond is largest in
A) $A$
B) $B$
C) $C$
D) $D$
Explanation
(c)
Element $C$ has electronic structure $1s^{2},2s^{2},2p^{5},$it requires only one electron to complete its octet and it will form anion so it will form electrovalent bond
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.