Q. Which one of the following linear structure? (I)$I_{3}^{-}$ (II)${NO}_{2}^{-}$ (III)$I_{3}^{+}$ (IV)$SO_{2}$ (V)$N_{3}^{-}$

A) I, II and III
B) I and V
C) II, III and IV
D) All of these
Explanation

(b)
$I_{3}^{-}$ ion is made up of an $I_{2}$ molecule with an $I^{-}$ bonded to it by means of a coordinate bond in which $I_{2}\$is lone pair acceptor (Lewis acid) and $I^{-}$ the lone pair donor (Lewis base). There are two bond pairs and three lone pairs in the outer shell of central atom. To minimize the repulsive forces the three lone pairs occupy the equatorial position. The ion is therefore, linear in shape with a bond angle of exactly $180{^\circ}$.
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Similarly, $N_{3}^{-}$ ion is also linear in shape.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.