Explanation

(d)
For $KO_{2},\ O_{2}^{-}$ has unpaired electron so, it is paramagnetic.
$O_{2}^{-}$(17)
$\ \sigma 1s^{2},\ _{\sigma}^{*}1s^{2}\ ,\sigma 2s^{2},\ _{\sigma}^{*}2s^{2}\ ,\ \sigma 2p_{x}^{2},(\sigma 2p_{y}^{2} = \sigma 2p_{z}^{2})$,
$\ \ _{\pi}^{*}2p_{y}^{2} = \ _{\pi}^{*}2p_{z}^{1}$