For AB bond if per cent ionic character is plotted against electronegativity difference $\left( X_{A} - X_{B} \right),\$the shape of the curve would look like [image:4_image46.emf] The correct curve is

Question

Dr. Abubacker · Accepted Answer

(c)
Per cent ionic character is given by % of ionic character.
$= 16\left( X_{A} - \ X_{B} \right) + 3.5\left( X_{A} - \ X_{B} \right)^{2}$
From the above relation, it is clear that as soon as $\left( X_{A} - \ X_{B} \right)\$increases, % ionic character will also increase.
Therefore, curve C shows a correct path.

Q. For AB bond if per cent ionic character is plotted against electronegativity difference $\left( X_{A} - X_{B} \right),\$the shape of the curve would look like

The correct curve is

Explanation

Reviewed by Dr. Abubacker

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Q. For AB bond if per cent ionic character is plotted against electronegativity difference $\left( X_{A} - X_{B} \right),\$the shape of the curve would look like The correct curve is

Explanation

Reviewed by Dr. Abubacker

Want more practice?

Q. For AB bond if per cent ionic character is plotted against electronegativity difference $\left( X_{A} - X_{B} \right),\$the shape of the curve would look like

The correct curve is