Q. A molecule (X) has (i) four sigma bonds formed by the overlap of $sp^{2}$ and s - orbitals (ii) one sigma bond formed by $sp^{2}$ and $sp^{2}$ orbitals and (iii) one $\pi$ bond formed by $p_{x}$ and $p_{z}$ orbitals. Which of the following is X?
A) $C_{2}H_{6}$
B) $C_{2}H_{3}Cl$
C) $C_{2}H_{2}Cl_{2}$
D) $C_{2}H_{4}$
Explanation
(d)
Structure of $C_{2}H_{4}$ is
[image:4_image167.jpeg]
[image:4_image168.jpeg]
So, the compound ($X$) is $C_{2}H_{4}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.