Explanation

(d)
The bond angle decreases with decrease in electronegativity. It results in decrease in repulsion between bond pair-bond pair electrons and bond angle becomes smaller.
Between $NH^{3}$ and $H_{2}O,\ H_{2}O$ has smaller bond angle due to presence of two lone pair of electrons causing more repulsion among electrons as compared of ${NH}^{3}$ which has only one lone pair of electron.
Hydrides $NH^{3}\ \ \ \ \ \ \ \ \ \ H_{2}O\ \ \ \ \ \ H_{2}S\ \ \ \ H_{2}Se\ \ \ \ \ H_{2}Te$
Bond angles $107{^\circ}\ \ \ 105{^\circ}\ \ \ \ \ \ 92{^\circ}\ \ \ \ \ \ 91{^\circ}\ \ \ \ \ \ \ \ \ 90{^\circ}$
$H_{2}\ Te$ has smallest bond angle.