Q. When $O_{2}$ is converted into $O_{2}^{+}$;
A) Both paramagnetic character and bond order increase
B) Bond order decreases
C) Paramagnetic character increases
D) Paramagnetic character decreases and the bond order increases
Explanation
(d)
$O_{2} = \sigma 1s^{2}\ _{\sigma}^{*}1s^{2}\sigma{2s}^{2}\ _{\sigma}^{*}2s^{2}\sigma 2p_{z}^{2}\pi 2p_{x}^{2} = \ \pi 2p_{y}^{2}\ _{\pi}^{*}2p_{x'} = \ _{\pi}^{*}2p_{y'}$
In $O_{2}^{+}$, one electron is removed from Na
BO for $O_{2} = 2$ and for $O_{2}^{+}$=2.5
Therefore, paramagnetism decreases, BO increases.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.