Q. Paramagnetism of oxygen is explained on the basis of its electronic configuration of
A) [image:4_image60.emf]
B) [image:4_image61.emf]
C) [image:4_image62.emf]
D) [image:4_image62.emf]
Explanation
(b)
The molecular electronic configuration of $O_{2}$ is
$O_{2\ }$= $\lbrack KK,\ (\sigma 2s)^{2},\ \left( \ _{\sigma}^{*}2s \right)^{2},\left( \sigma 2p_{x} \right)^{2},\ \left( \pi 2p_{y} \right)^{2}$
$\ \ \ \ \ \ = \left( \pi 2p_{z} \right)^{2},\ \left( \ _{\pi}^{*}2p_{y} \right)^{1} = \left( \pi 2p_{z} \right)^{1}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.