Q. In $XeF_{6},$ oxidation state and state of hybridisation of Xe and shape of the molecule are, respectively
A) $+ 6,sp^{3}\ d^{3},$ distorted octahedral
B) $+ 4,\ sp^{3}\ d^{2},$ square planar
C) $+ 6,\ sp^{3},\ pyramidal$
D) $+ 6,\ sp^{3}d^{2},\ square\ pyramidal$
Explanation
(a)
In $XeF_{6}$, the oxidation state of Xe is +6. The shape of $XeF_{6}$ should be pentagonal bipyramid due to $sp^{3}d^{3}$ hybridisation but due to$\$the presence of one lone pair at one trans position its shape becomes distorted octahedral.
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.