Q. From elementary molecular orbital theory we can give the electronic configuration of the singly positive nitrogen molecular ion $N_{2}^{+}$ as
A) $l\sigma 1s^{2},\sigma^{*}1s^{2},\sigma 2s^{2},\sigma^{*}2s^{2},\pi 2p^{4},\sigma 2p^{1}$
B) $\sigma 1s^{2},\sigma^{*}1s^{2},\sigma 2s^{2},\sigma^{*}2s^{2},\sigma 2p^{2},\pi 2p^{3}$
C) $\sigma 1s^{2},\sigma^{*}1s^{2},\sigma 2s^{2},\sigma^{*}2s^{2},\sigma 2p^{3},\pi 2p^{2}$
D) $\sigma 1s^{2},\sigma^{*}1s^{2},\sigma 2s^{2},\sigma^{*}2s^{2},\sigma 2p^{2},\pi 2p^{4}$
Explanation
The correct answer is Option A: $l\sigma 1s^{2},\sigma^{*}1s^{2},\sigma 2s^{2},\sigma^{*}2s^{2},\pi 2p^{4},\sigma 2p^{1}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.