Q. In a polar molecule, the ionic charge is $4.8 \times 10^{- 10}$ e.s.u. If the inter ionic distance is $1\ \mathring{\mathrm{A}}$ unit, then the dipole moment is
A) 41.8 debye
B) 4.18 debye
C) 4.8 debye
D) 0.48 debye
Explanation
(c)
Given ionic charge = $4.8 \times 10^{- 10}$ e.s.u. and ionic distance $= 1\mathring{\mathrm{A}} = 10^{- 8}$ cm. We know that dipole moment = Ionic charge $\times$ ionic distance
$= (4.8 \times 10^{- 10}) \times 10^{- 8}$
$\ = 4.8 \times 10^{- 18}$ e. s. u. per cm
$\ = 4.8$ debye.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.