Q. The decreasing order of bond angle is

A) $NO_{2} > {NO}_{2}^{+} > {NO}_{2}^{-}$
B) ${NO}_{2}^{-} > \ NO_{2} > {NO}_{2}^{+}$
C) ${NO}_{2}^{+} > \ NO_{2} > {NO}_{2}^{-}$
D) ${NO}_{2}^{+} > {NO}_{2}^{-} > \ NO_{2}$
Explanation

(c)
As the number of unpaired electrons (lone pair of electrons) increases, bond angle decreases. Thus, the decreasing order of bond angle is
Species : $\ \ \ \ \ \ {NO}_{2}^{+} > NO_{2} > \ {NO}_{2}^{-}$
Bond angle: $180{^\circ}\ \ \ \ \ \ 135{^\circ}\ \ \ \ \ \ \ 115{^\circ}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.