(b)
Formal charge = Number of electrons in valence shell –
$(\frac{1}{2} \times$numbers of electrons as bond pair$+$numbers of electrons as lone pair$)$
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For $N_{1}$ and $N_{3}$
Formal charge = $5 - \left( \frac{4}{2} + 4 \right) = 5 - (6) = - 1$
For ${\ N}_{2} = 5 - \frac{1}{2} \times 8 - 0 = 5 - 4 = + 1$