Q. For a given crystal, the lattice parameter ‘$a$’ is 318 pm. The $d$-spacing for a (III) plane is

A) 318 pm
B) 184 pm
C) 390 pm
D) 225 pm
Explanation

(b)
$d_{hkl} = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}}$
$d_{(111)} = \frac{a}{\sqrt{(1)^{2} + (1)^{2} + (1)^{2}}}$
$= \frac{a}{\sqrt{3}}$
$d_{(111)} = \frac{318}{\sqrt{3}} = 184\ pm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.