Q. One mole of oxygen at 273 K and one mole of sulphur di-oxide at 546 K are taken in two separate containers, then
A) Kinetic energy of $O_{2} > kinetic\ energy\ of\ {SO}_{2}$
B) Kinetic energy of $O_{2} < kinetic\ energy\ of\ {SO}_{2}$
C) Kinetic energy of both are equal
D) None of the above
Explanation
(b)
$KE = \frac{3}{2}\ RT$
$KE\ \propto T$
$\frac{{KE}_{O_{2}}}{{KE}_{{SO}_{2}}} = \frac{T_{O_{2}}}{T_{{SO}_{2}}} = \frac{273}{546} = \frac{1}{2}$
${KE}_{{SO}_{2}} = 2\ {KE}_{O_{2}}\$
${KE}_{{SO}_{2}} > \ {KE}_{O_{2}}\$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.