(a) According to Graham’s law $\frac{r_{O_{2}}}{r_{H_{2}}} = \sqrt{\frac{M_{H_{2}}}{M_{O_{2}}}}$ $\ \ \ \ \ \ \ = \sqrt{\frac{2}{32}}$ $\ \ \ \ \ \ \ = \frac{1}{4}$ $\therefore r_{O_{2}}:r_{H_{2}} = 1\ :4$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.