Q. An fcc lattice has a lattice parameter $a\$= 400 pm. Calculate the molar volume of the lattice including all the empty space
A) 7.6 mL
B) 6.5 mL
C) 10.8 mL
D) 9.6 mL
Explanation
(d)
Volume $= a^{3} = \left( 400 \times \ 10^{- 12}m \right)^{3} = 64 \times 10^{- 24}{cm}^{3}$
$V_{total} = VN_{A} = 64 \times 10^{- 24} \times \ 6.02 \times 10^{23}$
= 38.4
Molar volume$\ = \frac{1}{4} \times \ V_{total} = \ \frac{38.4}{4} = 9.6mL$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.