Q. If the temperature of 500 mL of air increases from $27℃\ to\ 42℃$ under constant pressure, then the increase in volume shall be
A) 15 mL
B) 20 mL
C) 25 mL
D) 30 mL
Explanation
(c)
Given, $V_{1} = 500\ mL,\ T_{1} = 27 + 273 = 300\ K$
$V_{2} = ?,\ T_{2} = 42 + 273 = 315\ K$
From Charles’ law
$\ \ \ V_{1}T_{2} = V_{2}T_{1}$
$\therefore V_{2} = \frac{500 \times 315}{300} = 525\ mL$
Hence, increase in volume $= 525 - 500$
$= 25\ mL$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.