Q. If two moles of a ideal gas at 546 K occupy volume 44.8 L, then pressure must be
A) 2 atm
B) 3 atm
C) 4 atm
D) 1 atm
Explanation
(a)
From gas equation, $pV = nRT$
Given that, $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ V = 44.8\ L$
$n = 2$
$R = 0.0821\ L\ atm\ {mol}^{- 1}\ K^{- 1}$
$T = 546\ K$
$\therefore\ p = \frac{2 \times 0.0821 \times 546}{44.8}$
$\ \ \ \ \ = 2\ atm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.