Q. A bubble of volume $V_{1}$ is in the bottom of a pond at $15℃$ and 1.5 atm pressure when it comes at the surface it observes a pressure of 1 atm at $25℃$ and have volume $V_{2}\ ,\ give\frac{V_{2}}{V_{1}}$
A) 15.5
B) 0.155
C) 155.0
D) 1.55
Explanation
(d)
$\ \ \ \ \ pV = nRT\ (Ideal\ gas\ equation)$
or $V = \frac{nRT}{p}$
$\ \ \ \ \ \ \frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}} \times \frac{p_{2}}{p_{1}}$
$\ \ \ \ \ \ \frac{V_{1}}{V_{2}} = \frac{273 + 15}{273 + 25} \times \frac{1}{1.5}$
$\ \ \ \ \ \ \frac{V_{1}}{V_{2}} = \frac{288}{298} \times \frac{1}{1.5}$
or $\frac{V_{1}}{V_{2}} = \frac{1}{1.55}$
or $\frac{V_{2}}{V_{1}} = 1.55$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.