(b) From Charles’ law $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $\frac{300\ mL}{300\ K} = \frac{V_{2}}{270\ K}$ $\left( V_{2} = 270\ mL \right)$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.