(b) Total kinetic energy $= \frac{3}{2}nRT$ Where, $n =$ number of moles of gas $\ \ \ \ \ \ \ \ \ \ \ \ \ \ n = 1$ Then, $KE = \frac{3}{2}\ RT$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.