Q. If the absolute temperature of a gas is doubled and the pressure is reduced to one half, the volume of the gas will
A) Remain unchanged
B) Be doubled
C) Increase four fold
D) Be halved
Explanation
(c)
For a gas,
$\frac{p_{1}V_{1}}{T_{1}} = \frac{p_{2}V_{2}}{T_{2}}\ \left( where,\ T_{2} = 2T_{1},\ p_{2} = \frac{1}{2}p_{1},\ V_{2} = ? \right)$
${\frac{p_{1}V_{1}}{T_{1}} = \frac{1}{2}\frac{p_{1} \times V_{2}}{2T_{1}}
}{V_{1} = \frac{V_{2}}{4}}$
$V_{2} = 4V_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.