Q. A certain mass of a gas occupies a volume of 2 L at STP. To what temperature the gas must be heated to double its volume, keeping the pressure constant?
A) 100 K
B) 273 K
C) $273℃$
D) $546℃$
Explanation
(c)
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\ \left( {Charles}^{'}\ law \right)$
$\frac{2}{273} = \frac{4}{T_{2}}$
$T_{2} = \frac{273 \times 4}{2} = 546\ K\ or\ 273℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.