Q. What is kinetic energy of 1 g of $O_{2}\ at\ 47℃?$
A) $1.24 \times 10^{2}\ J$
B) $2.24 \times 10^{2}\ J$
C) $1.24 \times 10^{3}\ J$
D) $3.24 \times 10^{2}\ J$
Explanation
(a)
Kinetic energy $= \frac{3w}{2M}\ RT$
where, $w =$ mass of a gas = 1 g
$M =$ molecular mass of gas = 32
$R = 8.314\ J\ K^{- 1}\ {mol}^{- 1}$
$T = 47{^\circ} + 273{^\circ} = 320\ K$
Kinetic energy $= \frac{3}{2} \times \frac{1}{32} \times 8.314 \times 320$
$= \frac{7981.44}{64} = 1.24 \times 10^{2}\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.