Q. 50 mL of hydrogen diffuses through small hole from a vessel in 20 min. Time taken for 40 mL of oxygen to diffuse out under similar conditions will be
A) 12 min
B) 32 min
C) 8 min
D) 64 min
Explanation
(d)
$\ \ \ \ \ \ \frac{r_{H_{2}}}{r_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H_{2}}}}$
$\frac{50/20}{40/t} = \ \sqrt{\frac{32}{2}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left( \because r = \frac{V}{t} \right)$
$\ \ \ \ \ \ \ \frac{t}{16} = 4\ \ \Rightarrow t = 64\ \min\$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.