Q. A gaseous mixture containing $He,\ CH_{4}$ and $SO_{4}$ was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? (Given mixture contains $He,CH_{4}$ and $SO_{2}$ in 1 : 2 : 3 mole ratio)
A) $\sqrt{2}:\sqrt{2}:3$
B) $2:2:3$
C) $4:4:3$
D) $1:1:3$
Explanation
(c)
$\frac{{n^{'}}_{He}^{'}}{{{{n^{'}}^{'}}_{CH}^{'}}_{4}} = \frac{1}{2}\ \sqrt{\frac{16}{4}} = \frac{1}{1}$
$\frac{{n^{'}}_{He}^{'}}{{{{n^{'}}^{'}}_{SO}^{'}}_{2}} = \frac{1}{3}\ \sqrt{\frac{64}{4}} = \frac{4}{3}$
So, ${n^{'}}_{He}^{'}:{{{n^{'}}^{'}}_{CH}^{'}}_{4}:{{{n^{'}}^{'}}_{SO}^{'}}_{2} = 4:4:3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.