(a)
The rate of effusion of He and ${CH}_{4}$
$\frac{r_{He}}{r_{{CH}_{4}}} = \sqrt{\frac{M_{{CH}_{4}}}{M_{He}}} = \sqrt{\frac{16}{4}} = 2\ :1$
If 4 : 1 mixture of He and ${CH}_{4}$ contained in a vessel, then the composition of mixture of He and ${CH}_{4}$ effusing out initially is 8 : 1.