Q. The interionic distance for cesium chloride crystal will be
A) $a$
B) $\frac{a}{2}$
C) $\frac{2a}{\sqrt{3}}$
D) $\frac{\sqrt{3}}{2}a$
Explanation
(d)
$CsCl$ has body centred arrangement, thus,
Interionic distance, $d = \frac{\sqrt{3a}}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.