(b) ${v_{H}}_{2} = {v_{O}}_{2}$ So, $\sqrt{{M_{O}}_{2}{T_{H}}_{2}} = \sqrt{{M_{H}}_{2}{T_{O}}_{2}}$ $32 \times {T_{H}}_{2} = 2 \times 1600$ ${T_{H}}_{2} = \frac{2 \times 1600}{32}$ $= 100\ K$
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Ph.D. in Physics with 19+ years of teaching experience.