An open vessel at $27℃$ is heated until 3/8^{th} of the air in it has been expelled. Assuming that the volume remains constant, calculate the temperature at which the vessel was heated

Question

Dr. Abubacker · Accepted Answer

(d)
According to Gay Lussac’s law
$\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}$
If $\frac{3^{th}}{8}$ of the air is expelled out then remaining air $= \frac{5}{8}$
$T_{2} = \frac{(273 + 27) 	imes 8}{5}$
$= \frac{2400}{5} = 480\ K$
$= 480 - 273 = 207℃$

Q. An open vessel at $27℃$ is heated until 3/8^{th} of the air in it has been expelled. Assuming that the volume remains constant, calculate the temperature at which the vessel was heated

Explanation

Reviewed by Dr. Abubacker

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