Q. Identify the pair of gases that have equal rates of diffusion

A) $CO,\ NO$
B) $N_{2}O,\ CO$
C) $N_{2}O,\ {CO}_{2}$
D) ${CO}_{2},\ {NO}_{2}$
Explanation

(c)
Rate of diffusion depends upon the molecular masses of gases. Therefore, the gases which have equal molecular mass, have equal rates of diffusion.
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
Molecular mass of $N_{2}O = 28 + 16 = 44$
Molecular mass of ${CO}_{2} = 12 + 32 = 44$
$\because\ \frac{r_{N_{2}O}}{r_{{CO}_{2}}} = 1$
$\therefore\ \ \ r_{N_{2}O} = r_{{CO}_{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.