Q. The temperature of 20 L of nitrogen was increased from 10 K to 30 K at a constant pressure. Change in volume will be
A) 20 L
B) 40 L
C) 60 L
D) 80 L
Explanation
(b)
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
$\frac{20}{10} = \frac{V_{2}}{30}\ \ \Rightarrow V_{2} = 60\ L$
$V_{2}\ –V_{1} = 60 - 20 = 40\ L$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.