Q. The density of $O_{2}$ is 16 at NTP. At what temperature its density will be 14? Consider that the pressure remains constant, at
A) $50℃$
B) $39℃$
C) $57℃$
D) $43℃$
Explanation
(b)
$\ \ \ \ \ \ \ \ \ d_{1}T_{1} = d_{2}T_{2}$
When $p$ remains constant
$\ \ \ \ \ \ \ \ \ \ \ \ \ d_{1} = 16;d_{2} = 14;T_{1} = 273\ K,\ T_{2} = ?$
$\ \ \ \ \ \ \ \ \ d_{1}T_{1} = d_{2}T_{2}$
$16 \times 273 = 14 \times T_{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ T_{2} = 312\ K$
$\ \ \ \ \ \ \ \ \ \ \ \ \ T_{2} = 312 - 273 = 39℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.