In $A^{+}B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are 180 pm and 187 pm respectively. The crystal structure of this compound will be

Question

Dr. Abubacker · Accepted Answer

(b)
$\frac{r_{+}}{r_{-}} = \frac{180}{187} = 0.962,$ which lies in the range of $0.732 - 1.000$, hence, coordination number 8, $ie$, the structure is $CsCl$ type

Q. In $A^{+}B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are 180 pm and 187 pm respectively. The crystal structure of this compound will be

Explanation

Reviewed by Dr. Abubacker

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