(b) $\frac{u_{1}}{u_{2}} = \sqrt{\frac{n_{1}T_{1}}{n_{2}T_{2}}} = \sqrt{\frac{n \times T}{2n \times 2T}} = \sqrt{\frac{1}{4}\ } = \frac{1}{2}$ $\therefore\ u_{2} = 2u_{1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.