The density of a gas $A$ is twice that of a gas $B$ at the same temperature. The molecular weight of gas $B$ is thrice that of $A$. The ratio of the pressures acting on $A$ and $B$ will be

Question

Dr. Abubacker · Accepted Answer

(a)
$\frac{d}{p} = \frac{M}{R}$
Let density of gas $B = d$
So, density of gas $A = 2d$
And molecular weight of $A = M$
So molecular weight of $B = 3M$
$p_{A} = \frac{M_{A}}{d_{A}}\ and\ \ p_{B} = \frac{M_{B}}{d_{B}}$
$\frac{p_{A}}{p_{B}} = \frac{M_{A}}{d_{A}} 	imes \frac{d_{B}}{M_{B}}$
$= \frac{M}{2d} 	imes \frac{d}{3M} = \frac{1}{6}$

Q. The density of a gas $A$ is twice that of a gas $B$ at the same temperature. The molecular weight of gas $B$ is thrice that of $A$. The ratio of the pressures acting on $A$ and $B$ will be

Explanation

Reviewed by Dr. Abubacker

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