Q. The average kinetic energy of an ideal gas per molecule in SI units at $25℃$ will be
A) $6.17 \times 10^{- 21}\ kJ$
B) $6.17 \times 10^{- 21}\ J$
C) $6.17 \times 10^{- 20}\ J$
D) $7.16 \times 10^{- 20}\ J$
Explanation
(b)
Average kinetic energy per molecule
$= \frac{3}{2}KT$
$= \frac{3}{2} \times 1.38 \times 10^{- 23} \times 300\ J$
$= 6.17 \times 10^{- 21}\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.