Q. An element occurring in the bcc structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be
A) $6.04 \times \ 10^{23}$
B) $12.08 \times \ 10^{23}$
C) $24.16 \times 10^{23}$
D) $36.18 \times \ 10^{23}$
Explanation
(c)
There are two atoms in a bcc unit cell
So, number of atoms in $12.08 \times 10^{23}$ unit cells
$= 2 \times 12.08 \times 10^{23}$
$= 24.16\ \times 10^{23}$ atoms
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.