Q. Kinetic energy of one mole of an ideal gas at 300 K in kJ is
A) 3.74
B) 348
C) 34.8
D) 3.48
Explanation
(a)
Kinetic energy (KE) $= \frac{3}{2}RT$
$\therefore\ \ \ KE = \frac{3}{2}\ \times 8.31 \times 300\ J$
$= 3.74\ kJ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.