Q. To what temperature must a neon gas sample be heated to double its pressure, if the initial volume of gas at $75℃$ is decreased by 15.0%?
A) $319℃$
B) $592℃$
C) $128℃$
D) $60℃$
Explanation
(d)
If $V_{1} = 1,\ V_{2} = 1 - \frac{15}{100} = \frac{17}{20}$
$p_{2} = 2p_{1}$
$T_{1} = 348,\ T_{2} = ?$
$\frac{p_{1}V_{1}}{T_{1}} = \frac{p_{2}V_{2}}{T_{2}}$
$\ \ \frac{p_{1}}{348} = 2p_{1} \times \frac{17}{20 \times T_{2}}$
$\ \ T_{2} = 60℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.