Q. Diffusion of helium gas is four times faster than
A) $CO_{2}$
B) $SO_{2}$
C) $NO_{2}$
D) $O_{2}$
Explanation
(b)
$Rate\ of\ diffusion\ of\ gas \propto \frac{1}{molecular\ mass}$
Let the molecular mass of other gas $= x$
$\because\frac{r_{He}}{r_{x}} = 4 = \sqrt{\frac{M_{x}}{M_{He}}}$
$\ \ \ \ \ \ \ 4 = \sqrt{\frac{M_{x}}{4}}$
$\ \ \ \ 4^{2} = \frac{M_{x}}{4}$
$\ \ \ M_{x} = 64\$
The gas having molecular mass 64 is ${SO}_{2}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.