(c) According to Graham’s law of diffusion $\ \ \ \ \frac{r_{O_{2\ }}}{r_{He}} = \sqrt{\frac{M_{He}}{M_{O_{2}}}}$ $or\ \ \ \ \ \ = \sqrt{\frac{4}{32}} = \frac{1}{2.83}$ $\therefore r_{O_{2}} = 0.35\ r_{He}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.