(d)
Given $T_{1} = 273 + 10 = 283\ K$
$\ \ \ \ \ \ \ \ \ \ \ \ T_{2} = 273 + 20 = 293\ K$
Average KE $= \frac{3}{2}kT$
$\frac{KE_{1}}{KE_{2}} = \frac{283}{293} = 0.96$
Root mean square (rms) velocity,
$\ \ \ \ \ v_{rms} = \sqrt{\frac{3RT}{M}}$
$\frac{v_{(rms)_{1}}}{v_{(rms)_{2}}} = \sqrt{\frac{T_{1}}{T_{2}}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \sqrt{\frac{283}{293}} = 0.98$
Thus both average kinetic energy and root mean square velocity increase but not significantly when temperature is increased from $10℃\ to\ 20℃.$