Q. A gaseous mixture of 2 moles of $A$, 3 moles of $B$, 5 moles of $C$ and 10 moles of $D$ is contained in a vessel. Assuming that gases are ideal and the partial pressure of $C$ is 1.5 atm, total pressure is

A) 3 atm
B) 6 atm
C) 9 atm
D) 15 atm
Explanation

(b)
Partial pressure $= \frac{no.of\ moles\ of\ gas \times p_{Total}}{total\ no.of\ moles}$
$1.5 = \frac{5 \times p_{total}}{2 + 3 + 5 + 10}$
$\frac{1.5 \times 20}{5} = p_{total}$
$p_{total} = 6\ atm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.