Q. 0.5 mole of each of $H_{2},\ SO_{2}$ and ${CH}_{4}$ are kept in a container. A hole was made in the container. After 3 h, the order of partial pressures in the container will be
A) $pSO_{2} > pH_{2} > pCH_{4}$
B) $pSO_{2} > pCH_{4} > pH_{2}$
C) $pH_{2} > p{SO}_{2} > pCH_{4}$
D) $pH_{2} > pCH_{4} > p{SO}_{2}$
Explanation
(b)
$Rate\ of\ diffusion \propto \frac{1}{\sqrt{molecular\ mass}}$
$\therefore Order\ of\ diffusion\ :H_{2} > {CH}_{4} > {SO}_{2}$
and amount left is in the order ${SO}_{2} > {CH}_{4} > H_{2}$
Hence, order of partial pressure is
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ p{SO}_{2} > p{CH}_{4} > pH_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.