Q. Analysis shows that an oxide ore of nickel has formula$\ Ni_{0.98}O_{1.00}.$ The percentage of nickel as $Ni^{3 +}$ ions is nearly
A) 2
B) 96
C) 4
D) 98
Explanation
(c)
Let the number of nickel ions =98
$\therefore$ The number of oxide ions =100
Total negative charge on $O^{2 -}$ ions$= 2 \times \ 100\ = 200$
Let number of $Ni^{2 +}$ ions $= 98\ –\ x$
$\therefore$ $x = 4$
% of Ni as $Ni^{3 +} = \frac{4}{98} \times \ 100 = 4.08\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.