Q. The temperature at which nitrogen under 1.00 atm pressure has the same root mean square as that of carbon dioxide at STP, is
A) $0℃$
B) $27℃$
C) $- 99℃$
D) $- 200℃$
Explanation
(c)
Let rms speed of nitrogen at $T$ K be $u$ and is equal to that of $CO_{2}$ at STP
$u_{rms} = \sqrt{\frac{3RT}{28}} = \sqrt{\frac{3R \times 273\ }{44}}$
$T = \frac{273 \times 28}{44}$
$= 173.73\ K = - 99.27℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.